Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Solve this problem A magnetic dipole is acted upon by two magnetic fields which are inclined to each other at an angle of 750. One of the fields has a magnitude of 15 mT. The dipole attains stable equilibrium at an angle of 300 with this field. The m

A magnetic dipole is acted upon by two magnetic fields which are inclined to each other at an angle of 750.  One of the fields has a magnitude of 15 mT.  The dipole attains stable equilibrium at an angle of 300 with this field.  The magnitude of the other field (in mT ) is close to :

  • Option 1)

    11

  • Option 2)

    36

  • Option 3)

    1

  • Option 4)

    1060

 

Answers (1)

best_answer

As we learnt in 

Torque -

\overrightarrow{\tau}=\overrightarrow{M}\times \overrightarrow {B}(where\ M=NiA)

\tau=MB\sin \theta =NBiA\sin \theta

 

- wherein

M - magnetic moment 

 

 For stable equilibrium, net torque acting on dipole must be zero

\vec{}\tau_1+ \vec{}\tau_{2}= 0

or,
\vec{}\tau_1 = \vec{}\tau_{2}

MB_1\sin \theta_1= MB_2\sin\theta_2

B_2=B_1\frac{\sin \theta_1}{\sin \theta_2}= 15mT\frac{\sin 30^0}{\sin 45^0}

B_2=15 mT\times \frac{1}{2} \times \sqrt{2}= 10.6 \:mT= 11\: mT


Option 1)

11

This is correct option.

Option 2)

36

This is incorrect option.

Option 3)

1

This is incorrect option.

Option 4)

1060

This is incorrect option.

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

What after JEE Main results 2024? All you need to know about JEE Adv, CSAB, JoSAA counselling

Latest Question