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  • Solve this problem A source (stationary) emits sound in a medium (non-absorbing). Two points A and B, are at distance 4 m & 9 m respectively from the source. The ratio of Amplitudes of waves at A and B is

A source (stationary) emits sound in a medium (non-absorbing). Two points A and B, are at distance 4 m & 9 m respectively from the source. The ratio of Amplitudes of waves at A and B is

  • Option 1)

    \frac{3}{2}

  • Option 2)

    \frac{4}{9}

  • Option 3)

    \frac{2}{3}

  • Option 4)

    \frac{9}{4}

 

Answers (1)

best_answer

I = \frac{p}{4\pi r^{2}}  since P = constant

I \alpha \frac{1}{r^{2}} and I \alpha A^{2}

\frac{A_{1}}{A_{2}} = \sqrt{\frac{I_{1}}{I_{2}}} = \frac{9}{4}

 

Intensity of periodic sound waves -

I= \frac{\Delta P{_{m}}^{2}}{2\rho v}
 

- wherein

\Delta P_{m}= Maxmium pressure change

\rho = density

v= velocity of sound

 

 

 

 


Option 1)

\frac{3}{2}

This is incorrect.

Option 2)

\frac{4}{9}

This is incorrect.

Option 3)

\frac{2}{3}

This is incorrect.

Option 4)

\frac{9}{4}

This is correct.

Posted by

Aadil

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