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  • Solve this problem A stone falls freely under gravity. It covers distancesh1,h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2and h3is:

A stone falls freely under gravity. It covers distances h1,h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is:

  • Option 1)

    h1=h2=h3

  • Option 2)

    h1=2h2=3h3

  • Option 3)

    h_{1}=\frac{h_{2}}{3}=\frac{h_{3}}{5}

  • Option 4)

    h2=3h1and h3=3h2

 

Answers (1)

best_answer

As we learned in

D_{n}\:=\:4+\frac{9}{2}(2n-1),\:\:D_{n}\propto (2n-1)

\therefore\:D_{1}:\:D_{2}\::D_{3}\:=\:1:3:5

h_{1}\:=\:\frac{h_{2}}{3}\:=\:\frac{h_{3}}{5}


Option 1)

h1=h2=h3

This option is incorrect.

Option 2)

h1=2h2=3h3

This option is incorrect.

Option 3)

h_{1}=\frac{h_{2}}{3}=\frac{h_{3}}{5}

This option is correct.

Option 4)

h2=3h1and h3=3h2

This option is incorrect.

Posted by

divya.saini

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