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  • Solve this problem - Chemical Thermodynamics - JEE Main-2

For the reactions,

C+O_{2}\rightarrow CO_2 \; ;           \Delta H=-393\, J

2Zn+O_2\rightarrow 2ZnO\, ;    \Delta H=-412\, J

  • Option 1)

    carbon can oxidise Zn

  • Option 2)

    oxidation of carbon is not feasible

  • Option 3)

    oxidation of Zn is not feasible

  • Option 4)

    Zn can oxidise carbon.

 

Answers (2)

best_answer

As we learnt in

Spontanous process -

\Delta G= \Delta H-\Delta T

 

- wherein

For spontanouse process \Delta G must be negative.

 

 

\Delta H is negative shows that the reaction is spontaneous. Higher negative value of Zn shows that the reaction is more feasible.


Option 1)

carbon can oxidise Zn

This option is incorrect 

Option 2)

oxidation of carbon is not feasible

This option is incorrect 

Option 3)

oxidation of Zn is not feasible

This option is incorrect 

Option 4)

Zn can oxidise carbon.

This option is correct 

Posted by

Aadil

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Answer 1

spontanous process

DeltaG is equal to deltaH minus delata t

Posted by

Killi jahnavi

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