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Solve this problem - Current Electricity - JEE Main-2

A moving coil galvanometer has resistance 50\Omega and it indicates full deflaction at 4mA current. A voltmeter is made using this galvanometer and a 5k\Omega resistance. The maximum voltage , that can be measured using this voltmeter,will be close to :

 

  • Option 1)

    40\: V

  • Option 2)

    15\: V

  • Option 3)

    20\: V

  • Option 4)

    10\: V

Answers (1)
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S solutionqc

Given    G=50\Omega

             i_{g}=4mA

Series resistance   S=5 k\Omega

     V=i_{g}\left ( G+S \right )

           =4\times 10^{-3}\left ( 5000+50 \right )

          =20.2\: V


Option 1)

40\: V

Option 2)

15\: V

Option 3)

20\: V

Option 4)

10\: V

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