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  • Solve this problem If a charge q is placed at the centre of the line joining two equal charges Q such that the system is in equilibrium then the value of q is

If a charge  q is placed at the centre of the line joining two equal charges Q  such that the system is in equilibrium then the value of q is 

  • Option 1)

    Q/2

  • Option 2)

    -Q/2

  • Option 3)

    Q/4

  • Option 4)

    -Q/4

 

Answers (2)

best_answer

As we learnt in

Superposition of Electric field -

The resultant electric field at any point is equal to the vector sum of all the electric fields.

 

- wherein

\vec{E}=\vec{E_{1}}+\vec{E_{2}}+\vec{E_{3}}+\cdots\vec{E_{n}}

 

 

When the system of three charges is in equilibrium,

\frac{Q\times q}{4\pi \varepsilon _{0}d^{2}}+\frac{Q\times Q}{4\pi \varepsilon _{0}\left ( 2d^{2} \right )}= 0

q= -\frac{Q}{4}


Option 1)

Q/2

Incorrect

Option 2)

-Q/2

Incorrect

Option 3)

Q/4

Incorrect

Option 4)

-Q/4

Correct

Posted by

Plabita

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