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  • Solve this problem Kcfor m1A + m2B = n1C + n2D is given by:

Kc for m1A + m2B = n1C + n2D is given by:

  • Option 1)

    Kc = \frac{[A]^{m_{1}}[B]^{m_{2}}}{[C]\times [D]}

  • Option 2)

    Kc = \frac{[A]^{m_{1}}[B]^{m_{2}}}{[C^{m_{1}}]\times [D]^{m_{2}}}

  • Option 3)

    Kc = \frac{[C]^{n_{1}}[D]^{n_{2}}}{[A]^{m_{1}}\times [B]^{m_{2}}}

  • Option 4)

    Kc = \frac{[C]^{n_{1}}[D]^{n_{2}}}{[A]^{n_{1}}\times [B]^{n_{2}}}

 

Answers (2)

best_answer

As we learnt in

Law of Chemical equilibrium -

At a given temperature, the product of concentration of the reaction products raised to the respective stoichiometric coefficient in the balanced chemical equation divided by the product of concentration of the reactants raised to their individual stoichiometric coefficients has a constant value.

- wherein

aA+bB\rightleftharpoons cC+dD


K_{c}=\frac{[C]^{c\:[D]^{d}}}{[A]^{a}\:[B]^{b}}

[A],\:[B],\:[C]\:[D]

are equilibrium concentration

 

m1A + m2B = n1C + n2D 

K_{c}=\frac{[C]^{n_1}\:[D]^{n_2}}{[A]^{m_1}\:[B]^{m_2}}

 

 


Option 1)

Kc = \frac{[A]^{m_{1}}[B]^{m_{2}}}{[C]\times [D]}

Incorrect

Option 2)

Kc = \frac{[A]^{m_{1}}[B]^{m_{2}}}{[C^{m_{1}}]\times [D]^{m_{2}}}

Incorrect

Option 3)

Kc = \frac{[C]^{n_{1}}[D]^{n_{2}}}{[A]^{m_{1}}\times [B]^{m_{2}}}

correct

Option 4)

Kc = \frac{[C]^{n_{1}}[D]^{n_{2}}}{[A]^{n_{1}}\times [B]^{n_{2}}}

Incorrect

Posted by

Plabita

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Posted by

Rohan

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