Three forces start acting simultaneously on a particle moving with velocity \vec{v}.These forces are represented in magnitude and direction by the three sides of a triangle ABC (as shown ).The particle will now move with velocity

  • Option 1)

    Less than \vec{v}

  • Option 2)

    greater than \vec{v}

  • Option 3)

    \left | \vec{v} \right | in the direction of the largest force BC

  • Option 4)

    \vec{v}remaining unchanged.

 

Answers (1)

As we learnt in

Equilibrium of Concurrent Forces -

If all the forces working on a body are acting on the same point then they are said to be concurrent.

- wherein

\sum \vec{F_{net}}= 0   

or \sum \vec{F_{x}}= 0,\sum \vec F_{y}= 0, \sum \vec F_{z}= 0

 

\ast  Three forces will be in equilibrium if they are represented by three sides of triangle taken in order

 

 

 By triangle of forces, the particle will be in equilibrium under the three forces. Obviously the resultant force on the particle will be zero. Consequently the acceleration will be zero. Hence the particle velocity remains unchanged at \vec{v}.

Correct option is 4.


Option 1)

Less than \vec{v}

This is an incorrect option.

Option 2)

greater than \vec{v}

This is an incorrect option.

Option 3)

\left | \vec{v} \right | in the direction of the largest force BC

This is an incorrect option.

Option 4)

\vec{v}remaining unchanged.

This is the correct option.

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