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# Engineering

A circular coil having N turns and radius r carries a current I. It is held in the XZ plane in a magnetic field B\widehat{i}. The torque on the coil due to the magnetic field is :
 

  • Option 1)

    \frac{B\pi r^{2}I}{N}

  • Option 2)

    B \pi r^{2}I\; N

  • Option 3)

    \frac{B r^{2}I}{\pi\: N}

     

  • Option 4)

    Zero

Answers (1)
S solutionqc

\vec{B} is along x

M= NIA

M is along y

\tau=M\times B=MB\; \sin \; 90=MB

\tau=NI(\pi\: r^{2})B

\tau=B\pi r^{2}I\; N


 


Option 1)

\frac{B\pi r^{2}I}{N}

Option 2)

B \pi r^{2}I\; N

Option 3)

\frac{B r^{2}I}{\pi\: N}

 

Option 4)

Zero

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