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  • Solve this problem One mole of mono atomic gas (γ = 5/3) is mixed with one mole of diatomic gas (γ = 7/5) what will be the value of γ for the mixture?

One mole of mono atomic gas (γ = 5/3) is mixed with one mole of diatomic gas (γ = 7/5) what will be the value of γ for the mixture?

  • Option 1)

    1.5

  • Option 2)

    2.5

  • Option 3)

    1.0

  • Option 4)

    2.0

 

Answers (1)

best_answer

As we learnt in 

Specific heat in isobaric process -

C_{p}= \left ( \frac{f}{2}+1 \right )R

\gamma^{mix}=\frac{n_{1}C_{p1}+n_{2}C_{p2}}{n_{1}C_{v1}+n_{2}C_{v2}}

 

- wherein

f is degree of freedom

 

 \gamma ^{mix}=\frac{n_1C_{p_1} +n_2C_{p_2}}{n_1C_{v_1}+n_2C_{v_2}}

C_{v_1} =\frac{3R}{2}, Cp_1=\frac{5R}{2}, n_1=1

C_{v_2} =\frac{5R}{2}, Cp_2=\frac{7R}{2}, \:n_2=1

\gamma ^{mix}= \frac{5R/2 + 7R/2}{3R/2+5R/2}=\frac{6R}{4R}=1.5

 


Option 1)

1.5

Correct

Option 2)

2.5

Incorrect

Option 3)

1.0

Incorrect

Option 4)

2.0

Incorrect

Posted by

Plabita

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