When  CH_2=CH-COOH is reduced with LiAlH_4, the compound obtained will be

  • Option 1)

    CH_3-CH_2-COOH

  • Option 2)

    CH_2=CH-CH_2OH

  • Option 3)

    CH_3-CH_2-CH_2OH

  • Option 4)

    CH_3-CH_2-CHO

 

Answers (1)

As we learnt in

Alcohol formation by reduction of carboxylic acids -

Yields primary alcohol.

- wherein

RCOOH+LiAlH_{4}\rightarrow RCH_{2}OH

 

 LiAlH_{4} can reduce COOH group and not the double bond.

CH_{2}= CH-COOH\overset{LiAlH_{4}}{\rightarrow}CH_{2}= CH-CH_{2}OH


Option 1)

CH_3-CH_2-COOH

This option is incorrect.

Option 2)

CH_2=CH-CH_2OH

This option is correct.

Option 3)

CH_3-CH_2-CH_2OH

This option is incorrect.

Option 4)

CH_3-CH_2-CHO

This option is incorrect.

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