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A metal has  FCC structure and the edge length of its unit cell is 3.04 \AA . The volume of the unit cell in cm3 will be

  • Option 1)

    1.6 X 10-21 cm3

  • Option 2)

    2.9 X 10-23 cm3

  • Option 3)

    6.02 X 10-23 cm3

  • Option 4)

    6.6 X 10-24 cm3

 

Answers (1)

best_answer

volume\: of\: cube=a^{3}

=\left ( 3.04\times 10^{-8} \right )^{3}

=2.9\times 10^{-23}cm^{3}

 

Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -

Image result for Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell

      AB^{2}=b^{2}=a^{2}+a^{2}.

                 b=4r.

             a=2\sqrt{2}r.

           

-

 

 


Option 1)

1.6 X 10-21 cm3

This is incorrect

Option 2)

2.9 X 10-23 cm3

This is correct

Option 3)

6.02 X 10-23 cm3

This is incorrect

Option 4)

6.6 X 10-24 cm3

This is incorrect

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Aadil

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