# A metal has  FCC structure and the edge length of its unit cell is 3.04 $\AA$ . The volume of the unit cell in cm3 will be Option 1) 1.6 X 10-21 cm3 Option 2) 2.9 X 10-23 cm3 Option 3) 6.02 X 10-23 cm3 Option 4) 6.6 X 10-24 cm3

$volume\: of\: cube=a^{3}$

$=\left ( 3.04\times 10^{-8} \right )^{3}$

$=2.9\times 10^{-23}cm^{3}$

Relation between radius of constituent particle, r and edge length, a for face centered cubic unit cell -

$AB^{2}=b^{2}=a^{2}+a^{2}.$

$b=4r.$

$a=2\sqrt{2}r.$

-

Option 1)

1.6 X 10-21 cm3

This is incorrect

Option 2)

2.9 X 10-23 cm3

This is correct

Option 3)

6.02 X 10-23 cm3

This is incorrect

Option 4)

6.6 X 10-24 cm3

This is incorrect

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