# The PH of boiling water (373k) is ............(Kw at 373K=10-12) Option 1) 12 Option 2) 8 Option 3) 6 Option 4) 2

P Prateek Shrivastava

As we learned in concept

p(Kw) -

$K_{w}=[H_{2}O^{+}]\:[H\bar{O}]=10^{-14}$

Although  $K_{w}$  may change with temperature the variation in pH with temperature are so small that we often ignore it.

- wherein

$p(K_{w})=-logK_{w}$

$=-log{[H_{3}O^{+}]\:[\bar{O}H]}$

$=-log10^{-14}$

$p(K_{w})=p(H)+p(OH)$

$=14$

$K_{w}=10^{-12}$

$=>\left [ H^{+} \right ]\left [ OH^{-} \right ]=10^{-12}$

$=>\left [ H^{+} \right ]^{2}=10^{-12}$

$=>\left [ H^{+} \right ]=10^{-6}$

$pH=-log\left [ H^{+} \right ]=-log(10^{-6})=6$

Option 1)

12

Option is incorrect

Option 2)

8

Option is incorrect

Option 3)

6

Option is correct

Option 4)

2

Option is incorrect

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