Two deuterons undergo nuclear fusion to form a Helium nucleus.  Energy released in this process is : (given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV)

  • Option 1)

    30.2 MeV

  • Option 2)

     32.4 MeV

  • Option 3)

     23.6 MeV

     

  • Option 4)

    25.8 MeV

 

Answers (1)

As we learnt in

Binding energy -

B.E=\left [ Zm_{p}+(A-Z)m_{n}-M_{x} \right ]c^{2} 

amount of energy released when nucleons  come together to form a nuclei.

M_{x} = mass of nuclei formed

 

- wherein

m_{p}- mass\ of\ proton

m_{n}- mass\ of \ neutron

Z- atomic\ number

A- atomic\ mass

 

 ^{2}_{1}D+^{2}_{1}D\rightarrow\ \; ^{4}_{2}He

Energy produced =-2m(^{2}_{1}D)+m(^{4}_{2}He)

=4\times7-4\times1.1=23.6\ MeV

Correct option is 3


Option 1)

30.2 MeV

This is an incorrect option.

Option 2)

 32.4 MeV

This is an incorrect option.

Option 3)

 23.6 MeV

 

This is the correct option.

Option 4)

25.8 MeV

This is an incorrect option.

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