Two deuterons undergo nuclear fusion to form a Helium nucleus.Energy released (in MeV ) in this process is : (given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV)

# Engineering

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV)

Option 1)
30.2 MeV

Option 2)
32.4 MeV

Option 3)
23.6 MeV

Option 4)
25.8 MeV

Answers (1)

P perimeter

As we learnt in

Binding energy -

$B.E=\left [ Zm_{p}+(A-Z)m_{n}-M_{x} \right ]c^{2}$

amount of energy released when nucleons come together to form a nuclei.

$M_{x}$ = mass of nuclei formed

- wherein

$m_{p}- mass\ of\ proton$

$m_{n}- mass\ of \ neutron$

$Z- atomic\ number$

$A- atomic\ mass$

$^{2}_{1}D+^{2}_{1}D\rightarrow\ \; ^{4}_{2}He$

Energy produced $=-2m(^{2}_{1}D)+m(^{4}_{2}He)$

$=4\times7-4\times1.1=23.6\ MeV$

Correct option is 3

Option 1)

30.2 MeV

This is an incorrect option.

Option 2)

32.4 MeV

This is an incorrect option.

Option 3)

23.6 MeV

This is the correct option.

Option 4)

25.8 MeV

This is an incorrect option.

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Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV) Option 1) 30.2 MeV Option 2) 32.4 MeV Option 3) 23.6 MeV Option 4) 25.8 MeV

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Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron=1.1 MeV and for helium=7.0 MeV)

Option 1)
30.2 MeV

Option 2)
32.4 MeV

Option 3)
23.6 MeV

Option 4)
25.8 MeV