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Two solids dissociate as follows

$A(s)\rightleftharpoons B(g)+C(g);K_{p1}=x\: atm^{2}$

$D(s)\rightleftharpoons C(g)+E(g);K_{p2}=y\: atm^{2}$

The total pressure when both the solids dissociate simultaneously is :
Option 1)
(x + y) atm
Option 2)
$\sqrt{x +y}\: atm$

Option 3)
$x^{2}+y^{2} \: atm$
Option 4)
$2 (\sqrt{x+y})atm$

Answers (1)

A admin

Relation between pressure and concentration -

$PV=nRT$

$or\:P=\frac{n}{V}RT$

$or\:P=CRT$

$R=0.0831\:bar\:inter/mol\:K$

- wherein

P is pressure in Pa. C is concentration in mol / litre. T is temperature in kelvin

As we have learned in total pressure at equilibrium

$A_{\left ( s \right )}\rightleftharpoons B_{\left ( g \right )}+C_{\left ( g\, \right )}\, \, K_{p}= xatm^{2}$

$D_{\left ( s \right )}\rightleftharpoons C_{\left ( g \right )}+E_{\left ( g \right )}\, \, Kp_{2}= yatm^{2}$

$p_{1}+p_{2 }\, \, \, \, \, \, \, \, p_{2}$

$Kp_{1}= p_{1}\left ( p _{1}+p_{2}\right )$ $Kp_{2}= p_{2}\left ( p _{1}+p_{2}\right )$

$Kp_{2}= p_{2}\left ( p _{1}+p_{2}\right )^{2}$

$x+y= \left ( p_{1+} p_{2}\right )^{2}$

$\left ( p_{1+} p_{2}\right )= \sqrt{x+y}$

$P_{total}= P_{b}+P_{c}+P_{e}$

$= 2\left ( p_{1+}p_{2} \right )=2\sqrt{x+y}$

Option 1)

(x + y) atm

Option 2)

$\sqrt{x +y}\: atm$

Option 3)

$x^{2}+y^{2} \: atm$

Option 4)
$2 (\sqrt{x+y})atm$

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