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  2. Solve! - Two solids dissociate as follows The total pressure when both the solids dissociate simultaneousl - Equilibrium - JEE Main
# Engineering

Two solids dissociate as follows 

A(s)\rightleftharpoons B(g)+C(g);K_{p1}=x\: atm^{2}

D(s)\rightleftharpoons C(g)+E(g);K_{p2}=y\: atm^{2}

The total pressure when both the solids dissociate simultaneously is :

  • Option 1)

    (x + y) atm

  • Option 2)

    \sqrt{x +y}\: atm

     

  • Option 3)

    x^{2}+y^{2} \: atm

  • Option 4)

    2 (\sqrt{x+y})atm

     

Answers (1)
A admin

 

Relation between pressure and concentration -

PV=nRT

or\:P=\frac{n}{V}RT

or\:P=CRT

R=0.0831\:bar\:inter/mol\:K

- wherein

P is pressure in Pa. C is concentration in mol / litre. T is temperature in kelvin 

As we have learned in total pressure at equilibrium

A_{\left ( s \right )}\rightleftharpoons B_{\left ( g \right )}+C_{\left ( g\, \right )}\, \, K_{p}= xatm^{2}

D_{\left ( s \right )}\rightleftharpoons C_{\left ( g \right )}+E_{\left ( g \right )}\, \, Kp_{2}= yatm^{2}

p_{1}+p_{2 }\, \, \, \, \, \, \, \, p_{2}

Kp_{1}= p_{1}\left ( p _{1}+p_{2}\right )                      Kp_{2}= p_{2}\left ( p _{1}+p_{2}\right )

Kp_{2}= p_{2}\left ( p _{1}+p_{2}\right )^{2}

x+y= \left ( p_{1+} p_{2}\right )^{2}

\left ( p_{1+} p_{2}\right )= \sqrt{x+y}

P_{total}= P_{b}+P_{c}+P_{e}

= 2\left ( p_{1+}p_{2} \right )=2\sqrt{x+y}

 


Option 1)

(x + y) atm

Option 2)

\sqrt{x +y}\: atm

 

Option 3)

x^{2}+y^{2} \: atm

Option 4)

2 (\sqrt{x+y})atm

 

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