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  • Solve! What is the percentage purity of a sample of CaCO3if 150 g of the sample gives out 44 g of CO2on heating?

What is the percentage purity of a sample of CaCO3 if 150 g of the sample gives out 44 g of CO2 on heating?

  • Option 1)

    33.33%

  • Option 2)

    66.67%

  • Option 3)

    75%

  • Option 4)

    50%

 

Answers (2)

best_answer

As we learnt in

Number of Moles -

No of moles = given mass of substance/ molar mass of substance

-

 

 Moles of CO2 emitted =\frac{44}{44}=1\ mole

So, moles of CaCO3 = 1

So, mass of CaCO3 = 40 + 12 + 48 = 100

Percentage purity =\frac{100 \times 100}{50}=66.67\%

 


Option 1)

33.33%

Incorrect

Option 2)

66.67%

Correct

Option 3)

75%

Incorrect

Option 4)

50%

Incorrect

Posted by

prateek

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Number of Moles -

No of moles = given mass of substance/ molar mass of substance

-

 

 Moles of CO2 emitted =\frac{44}{44}=1\ mole

So, moles of CaCO3 = 1

So, mass of CaCO3 = 40 + 12 + 48 = 100

Percentage purity = \frac{50}{100}*100\frac{50}{100}*100=50%\frac{50}{100}*100=50%

\frac{50}{100}*100=50% Correct answer- Option 4) 50%

Posted by

Zulqarnain Qazi

View full answer

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