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A positronium atom is a system that consists of a positron and an electron that orbit each other. Ratio of wavelength of spectral line of positronium to that of ordinary hydrogen is:

Option: 1

2:1


Option: 2

4:1


Option: 3

1:2


Option: 4

1:4


Answers (1)

best_answer

As we learn

Effect of nucleas motion on energy of atom -

E_{n}^{1}= E_{n}\left ( \frac{m_{N}}{m_{e}+m_{N}} \right )

- wherein

E_{n}^{1}=  Energy of nth orbital with nucleus motion

E_{n}=Energy of nth orbital without nucleus motion

m_{e}=mass of electron

m_{N}=mass of nucleus

 

 since the two particle has same mass        \mu =\frac{m*m}{m+m}=\frac{m}{2}

since         E_{n}\propto m  

\frac{E_{n}^{'}}{E_{n}}=\frac{1}{2}

Hence energy level of positronium atom is half of the corresponding energy level in H-atom.

 As a result the wavelength in the positronium atom spectral lines is twice those of corresponding lines in hydrogen spectrum.

 

Posted by

Rishi

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