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When \mathrm{HCOOH} reacts with conc.\mathrm{ H_2SO_4} it gives:

Option: 1

\mathrm{CO_2}


Option: 2

\mathrm{HCHO}


Option: 3

\mathrm{CO+H_2O}


Option: 4

\mathrm{CH_3OH}


Answers (1)

best_answer

As we have learnt,

Dehydration of formic acid \mathrm{(HCOOH)} with conc. \mathrm{H_2SO_4} forms \mathrm{CO}

\mathrm{HCOOH \xrightarrow[conc. H_{2}SO_{4}]{373 K}H_{2}O +CO}

Therefore, option (3) is correct.

Posted by

HARSH KANKARIA

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