Light of wavelength shines on a metal and emits Y electrons per second of average energy Z. What will happen to Y and Z if intensity of light is doubled?
Y will be doubled and Z will be halved
Y will remain same and Z will be doubled.
Both Y and Z will be doubled.
Y will increase but Z will remain same.
When intensity is doubled, it means that the brightness of the light is doubled but the energy of the incident beam is kept the same.
So on increasing the number of incident photons, the number of electrons emitted per second will increase but average energy of photoelectrons emitted remains the same.
Therefore, the correct option is (4)