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Spin only magnetic moment of an octahedral complex of \mathrm{Fe}^{2+} in the presence of a strong field ligand in BM is :
Option: 1 4.89
Option: 2 4.89
Option: 3 4.89
Option: 4 4.89
Option: 5 2.82
Option: 6 2.82
Option: 7 2.82
Option: 8 2.82
Option: 9 0
Option: 10 0
Option: 11 0
Option: 12 0
Option: 13 3.46
Option: 14 3.46
Option: 15 3.46
Option: 16 3.46

Answers (1)

best_answer

Electionic configuration of  \mathrm{Fe}^{2+}=[\mathrm{Ar}] 3 \mathrm{~d}^{6}

In the preserce of a strong field ligand, pairing will take place

Thus there are no unpaired electrons and the spin only magnetic moment is zero.

Hence, the correct answer is option (3)

Posted by

sudhir.kumar

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