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  • Spin only magnetic moment of  is ______ B.M.(round off to

Spin only magnetic moment of \left[\mathrm{MnBr}_{6}\right]^{4-} is ______ B.M.(round off to the closest integer)

Option: 1

6


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{\left[\mathrm{MnBr}_{6}\right]^{4-} \Rightarrow M n^{2+}}   with weak field ligard

\mathrm{M n^{2+} \rightarrow t_{2g}^{1,1,1} e_g^{1,1}}      

\mathrm{\mu_{S}=\sqrt{n(n+2)} ~B. M. }

\mathrm{\mu_s=\sqrt{5(5+2)} \text { B.M. }}

\\\mathrm{\mu_s=\sqrt{35} \text { B.M. }}

\mathrm{\mu_s=5.91 ~B. M. }

Hence the answer is 6 when rounded off to nearest integer.

 

 

Posted by

Kuldeep Maurya

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