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  • Stability of the species ,<img alt="Li_{2},Li_{2}^{-} \: and\: Li_{2}^{+}" src="https://learn.careers360.com/latex-image/?%5Cdpi%7B100%7D%20Li_%7B2%7D%2CLi_%7B2%7D%5E%7B-%7D%20%5C%3A%20and%5C%3A%20

Stability of the species ,Li_{2},Li_{2}^{-} \: and\: Li_{2}^{+} increases  in the order of :

Option: 1

Li_{2}^{-}< Li_{2}< Li_{2}^{+}


Option: 2

Li_{2}< Li_{2}^{+}< Li_{2}^{-}


Option: 3

Li_{2}^{-}< Li_{2}^{+} <Li_{2}


Option: 4

Li_{2}<Li_{2}^{-}< Li_{2}^{+}


Answers (1)

best_answer

As we discussed in the concept

Stability of molecules -

1.  Molecule is stable if Nb is greater than Na and 

2.  The molecule is unstable if Nb is less than Na  

- wherein

Nb = number of bonding electron 

Na = number of antibonding electron

 

 Higher the value of bond higher will be the stability. If value of bond order is same then lower the value of electrons higher will be the stability.

L^{-}_{i2}= Nb= 4,Na=3, Bond\:order =0.5

L^{+}_{i2}= Nb= 3,Na=2, Bond\:order =0.5

L_{i2}= Nb= 3,Na=3, Bond\:order =1

Order of stability L^{-}_{i2}< L^{+}_{i2}< L_{i2}

 

 

 

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chirag

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