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Q  Calculate the number of atoms in a cubic based unit cell having one atom on each corner and two atoms on each body diagonal. 

A.9

B.8

C.7

D.10

What is body diagonal? how to calculate?

 

Answers (1)

There are four body diagonals and atoms on the body diagonal are not shared by any other unit cell.

 Atoms at the corner =8 \times \frac{1}{8}=1$ 


Atoms on the body diagonal=2 \times 4=8$
Total number of atoms =1+8=9

Posted by

Satyajeet Kumar

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