In a hydrogen atom, if energy of an electron in ground state is 13.6eV then that in the 2nd excited state is

  • Option 1)

    1.51 eV

  • Option 2)

    3.4 eV

  • Option 3)

    6.04 eV

  • Option 4)

    13.6 eV

 

Answers (2)

As we learnt in 

Total energy of elctron in nth orbit -

E_{n}= -13.6\: \frac{z^{2}}{n^{2}}eV

Where z is atomic number

-

 

 2nd excited state will be the 3rd  energy level.

E_{n}= -13.6\: \frac{z^{2}}{n^{2}}eV

=\frac{ -13.6\times 1^{^{2}}}{3^2} eV

= 1.51eV


Option 1)

1.51 eV

Correct Option

Option 2)

3.4 eV

Incorrect Option

Option 3)

6.04 eV

Incorrect Option

Option 4)

13.6 eV

Incorrect Option

N neha

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