He^{+} ion is in its first excited state . Its ionization energy is :

  • Option 1)

    48.36\:\:eV

  • Option 2)

    54.40\:\:eV

  • Option 3)

    13.60\:\:eV

  • Option 4)

    6.04\:\:eV

 

Answers (1)

we know that ,

E_{n}=-13.6 \left ( \frac{Z^{2}}{n^{2}} \right )

in first excited state for He^{+}

\Rightarrow n=2,Z=2

E=-13.6\times\left ( \frac{2^{2}}{2^{2}} \right )=-13.6\:eV

\Rightarrow Ionisation\:\:\:energy=+13.6\:eV

 


Option 1)

48.36\:\:eV

Option 2)

54.40\:\:eV

Option 3)

13.60\:\:eV

Option 4)

6.04\:\:eV

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Test Series JEE Main April 2022

Take chapter-wise, subject-wise and Complete syllabus mock tests and get an in-depth analysis of your test..

₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions