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# Engineering

The correct order of the spin-only magnetic moment of metal ions in the following law-spin complexes,

\left [ V(CN)_{6} \right ]^{4-},\left [ Fe(CN)_{6} \right ]^{4-},\left [ Ru(NH_{3}) _{6}\right ]^{3+},and\left [ Cr\left ( NH_{3} \right )_{6} \right ]^{2+}is:
 

  • Option 1)

    Cr^{2+}>V^{2+}>Ru^{3+}>Fe^{2+}

  • Option 2)

    Cr^{2+}>Ru^{3+}>Fe^{2+}>V^{2+}

  • Option 3)

    V^{2+}>Cr^{2+}>Ru^{3+}>Fe^{2+}

     

  • Option 4)

    V^{2+}>Ru^{3+}>Cr^{2+}>Fe^{2+}

Answers (1)
S solutionqc

                                  Configuration                No.of unpaired electron

    V(CN)_{6}^{4-}\; \; \; \; \; \; \; \; \; t2g^{3}eg^{o}\; \; \; \; \; \; \; \;\; \; \; \; \; \; 3

    [Cr(NH_{3})_{6}]^{2+}\; \; \; \; \; \; \; t2g^{4}eg^{o}\; \; \; \; \; \; \; \; \; \; 2 

   [Ru(NH_{3})_{6}]^{3+}\; \; \; \; \; \; t2g^{5}eg^{o}\; \; \; \; \; \; \; \; \; \; \; \; 1

   [Fe(CN)_{6}]^{4-}\; \; \; \; \; \; \; t2g^{6}eg^{o}\; \; \; \; \; \; \; \; \; \; \; \; 0

 

V^{2+}>Cr^{2+}>Ru^{3+}>Fe^{2+}

 


Option 1)

Cr^{2+}>V^{2+}>Ru^{3+}>Fe^{2+}

Option 2)

Cr^{2+}>Ru^{3+}>Fe^{2+}>V^{2+}

Option 3)

V^{2+}>Cr^{2+}>Ru^{3+}>Fe^{2+}

 

Option 4)

V^{2+}>Ru^{3+}>Cr^{2+}>Fe^{2+}

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