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  • Stuck here, help me understand: - Complex numbers and quadratic equations - JEE Main-4

Let \alpha is a root of  ax^{2}+bx+c= 0  then a\alpha ^{3}+\left (a+b \right )\alpha ^{2}+\left (b+c \right )\alpha+c  equals

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Answers (1)

best_answer

\alpha is root of  ax^{2}+bx+c= 0

 ax^{2}+bx+c= 0

now , a\alpha ^{3}+ \left ( a+b \right )\alpha ^{2} + \left ( b+c \right )\alpha +c = a\alpha ^{3} +a\alpha ^{2}+b\alpha ^{2}+b\alpha +c\alpha +c

=0+0

=0

 

Roots of Quadratic Equation with real Coefficients -

\alpha ,\beta are roots if

ax^{2}+bx+c= 0

is satisfied by x= \alpha ,\beta

 

- wherein

\alpha ,\beta\in C

a,b,c\in R

 

 

 


Option 1)

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Option 2)

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Option 3)

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Option 4)

0

This is correct

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Himanshu

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