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Number of integer values of 'a' for which x^{2}+2\left ( a-1 \right )x+a\geqslant -5   \forall   x\: \epsilon \: R  is

  • Option 1)

    6

  • Option 2)

    5

  • Option 3)

    4

  • Option 4)

    3

 

Answers (1)

best_answer

x^{2}+2\left ( a-1 \right )x+\left ( a+5 \right )\geqslant 0\: \forall \: n\, \epsilon \, R

So D\leqslant 0 is only required condition here as coefficient of x^{2} is already positive.

4\left ( a-1 \right )^{2}-4\left ( a+5 \right )\leqslant 0\: \Rightarrow \: \left ( a-4 \right )\left ( a+1 \right )\leqslant 0

\Rightarrow \: a\, \epsilon \, \left [ -1,4 \right ]

\therefore Option (A)

 

Quadratic Expression ax^2 + bx + c is non negative -

ax^{2}+bx+c\geqslant 0 for all x \epsilon R  When  a> 0  &   b^{2}-4ac\leq 0    \left ( \; a,b,c\; \epsilon\; R \right )

 

 

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Option 1)

6

This is correct

Option 2)

5

This is incorrect

Option 3)

4

This is incorrect

Option 4)

3

This is incorrect

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