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Stuck here, help me understand: - Current Electricity - JEE Main

A moving coil galvanometer allows a full  scale current of 10^{^{-2}} A. A series resistance  of 200\Omega is required to convert the above galvanometer into an voltmeter of range0-5 V . Therefore the value of shunt resistance required to convert the above galvanometer into an ammeter of range0-10 mA is :

  • Option 1)

    300\Omega

  • Option 2)

    100\Omega

  • Option 3)

    200\Omega

  • Option 4)

    10\Omega

 
Answers (1)
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Conversion of galvanometer into voltameter -

Connected a large Resistance R  in series

- wherein

 

 

(R+G) I = V

(2\times 10^{2}+G)10^{-2}=V=5

=> 2+10^{-2}G=5

 G=300\Omega


Option 1)

300\Omega

Option 2)

100\Omega

Option 3)

200\Omega

Option 4)

10\Omega

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