To verify Ohm's law, a student connects the voltmeter across the battery as, shown in the figure. The measured voltage is plotted as a function graph is obtained :

If V_{0} is almost zero, identify the correct statement :

  • Option 1)

    The potential difference across the battery is 1.5V when it sends a current of 1000mA

  • Option 2)

    The emf of the battery is 1.5V and the value of R is 1.5\Omega

  • Option 3)

    The emf of the battery is 1.5V and its internal resistance is 1.5\Omega

  • Option 4)

    The value of the resistance R is 1.5\Omega

 

Answers (1)

When I is zero in the graph, V=1.5V which is EMF of the will

E=1.5V

Also when V=V_{0}=zero, then E=ir

              \Rightarrow 1.5=(1000mA)r

             \Rightarrow r=1.5\Omega


Option 1)

The potential difference across the battery is 1.5V when it sends a current of 1000mA

Option 2)

The emf of the battery is 1.5V and the value of R is 1.5\Omega

Option 3)

The emf of the battery is 1.5V and its internal resistance is 1.5\Omega

Option 4)

The value of the resistance R is 1.5\Omega

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