In a compound, atoms of element Y from ccp lattice and those of element occupy 2/3rd  of tetrahedral voids. The formula of the compound will be

  • Option 1)

    X_{3}Y_{4}

  • Option 2)

    X_{4}Y_{3}

  • Option 3)

    X_{2}Y_{3}

  • Option 4)

    X_{2}Y

 

Answers (1)

As we learnt in

No. of atoms(z) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- wherein

 

 

 

Number of Y  atoms per unit cell in ccp  lattice (N)=4

number of tetrahedral voids 2N=2\times 4= 8

number of tetrahedral voids occupied by X

    = 2/3^{rd}of \: the\: tetrahedral \: void\: = 2/3\times 8= 16/3

Hence the formula of the compound will be

X_{16/3}Y_{4}= X_{4}Y_{3}

Correct option is 2.


Option 1)

X_{3}Y_{4}

This is an incorrect option.

Option 2)

X_{4}Y_{3}

This is the correct option.

Option 3)

X_{2}Y_{3}

This is an incorrect option.

Option 4)

X_{2}Y

This is an incorrect option.

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