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  • Stuck here, help me understand: In diamond C atom occupy each corner, each face centre and 50% tetrahedral void , distance between the two nearest C atom is -(Edge length of unit cell is a )

In diamond C atom occupy each corner, each face centre and 50% tetrahedral void , distance between the two nearest C atom is -

(Edge length of unit cell is a )

  • Option 1)

    \frac{\sqrt{3}a}{8}

  • Option 2)

    \frac{\sqrt{3}a}{4}

  • Option 3)

    \frac{\sqrt{3}a}{2}

  • Option 4)

    {\sqrt{3}a}

 

Answers (1)

best_answer

In diamond the e atom at corner and tetrahedral voids are nearest neighbour and distance between a corner and terahedral void is \frac{a\sqrt{3}}{4}

 

 

Distance between corner atom and tetrahedral void -

\frac{\sqrt{3}a}{4}

- wherein

a = edge length of cube

 

 


Option 1)

\frac{\sqrt{3}a}{8}

This is incorrect

Option 2)

\frac{\sqrt{3}a}{4}

This is correct

Option 3)

\frac{\sqrt{3}a}{2}

This is incorrect

Option 4)

{\sqrt{3}a}

This is incorrect

Posted by

divya.saini

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