In figure is shown a system of four capacitors connected across a 10 V battery. Charge that will flow from switch S when it is closed is :

  • Option 1)

    5 \: \mu C\: f\! rom\: b\: to\: a

  • Option 2)

    20 \: \mu C\: f\! rom\: a\: to\: b

  • Option 3)

    5 \: \mu C\: f\! rom\: a\: to\: b

  • Option 4)

    zero

 

Answers (2)

As we learnt in 

Series Grouping -

\frac{1}{C_{eq}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\cdots

- wherein

 

 

Parallel Grouping -

 

C_{eq}=C_{1}+C_{2}+\cdots

- wherein

 

 For upper and lower links C_{eq}= \frac{6}{5}\mu F

\therefore Q_{upper}= Q_{lower}= 12\mu C

On closing switch charge on 2\mu F is 10\mu F and that on 3\mu F is 15\mu F.

At a, 

q_{i}= -12+12= 0

q_{f}= 15-10= 5\mu C

\therefore 5\mu C flows from b to a. 


Option 1)

5 \: \mu C\: f\! rom\: b\: to\: a

Correct option

Option 2)

20 \: \mu C\: f\! rom\: a\: to\: b

Incorrect option

Option 3)

5 \: \mu C\: f\! rom\: a\: to\: b

Incorrect option

Option 4)

zero

Incorrect option

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