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  • Stuck here, help me understand: In the block spring system. Force constant of a spring is K = 6 N/m. Spring is Streached by 12cm and then left. Find out the angular frequency of oscillation

In the block spring system. Force constant of a spring is  K = 6 N/m. Spring is Streached by 12cm and then left. Find out the angular frequency of oscillation

  • Option 1)

    3rad/s

  • Option 2)

    1.3 rad/s

  • Option 3)

    6 rad/s

  • Option 4)

    1 rad/s

 

Answers (1)

\omega = \sqrt{\frac{K}{reduced\;mass}} \Rightarrow \omega = \sqrt{\frac{K}{M}}

M = \frac{m_{1}m_{2}}{m_{1}+m_{2}} = \frac{2}{3}\;kg

\omega = \sqrt{\frac{6}{\frac{2}{3}}} = 3\;rad/s

 

Oscillation of two - particle system -

T=2\pi \sqrt{\frac{\mu }{K}}

- wherein

where \mu = \frac{m_{1}m_{2}}{m_{1}+m_{2}} is called reduced mass.

K is spring constant

 

 

 


Option 1)

3rad/s

This is correct.

Option 2)

1.3 rad/s

This is incorrect.

Option 3)

6 rad/s

This is incorrect.

Option 4)

1 rad/s

This is incorrect.

Posted by

subam

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