In the following compounds, the decreasing order of basic strength will be :

 

  • Option 1)

    C_{2}H_{5}NH_{2}>NH_{3}>(C_{2}H_{5})_{2}NH
     

  • Option 2)

    NH_{3}>C_{2}H_{5}NH_{2}>(C_{2}H_{5})_{2}NH

  • Option 3)

    (C_{2}H_{5})_{2}NH>C_{2}H_{5}NH_{2}>NH_{3}

     

  • Option 4)

    (C_{2}H_{5})_{2}NH>NH_{3}>C_{2}H_{5}NH_{2}

Answers (1)

(C_{2}H_{5})_{2}NH>C_{2}H_{5}NH_{2}>NH_{3}

NH_{3}\: \: (C_{2}H_{5})_{2}\ddot{N}H\: \: \: \: C_{2}H_{5}NH_{2}

+I \: Order:-\: Et_{2}\ddot{N}H> EtNH_{2}>NH_{3}

Solution \: Order:-\: NH_{3}>EtNH_{2}>Et_{2}\ddot{N}H

Both\: Order\: addition:-\: Et_{2}\ddot{N}H>EtNH_{2}>\ddot{N}H_{3}


Option 1)

C_{2}H_{5}NH_{2}>NH_{3}>(C_{2}H_{5})_{2}NH
 

Option 2)

NH_{3}>C_{2}H_{5}NH_{2}>(C_{2}H_{5})_{2}NH

Option 3)

(C_{2}H_{5})_{2}NH>C_{2}H_{5}NH_{2}>NH_{3}

 

Option 4)

(C_{2}H_{5})_{2}NH>NH_{3}>C_{2}H_{5}NH_{2}

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