Calculate molar conductance of acetic acid using appropriate molar conductances of the electrolytes listed above at infinite dilution in H_{2}O at 25°C.

  • Option 1)

    517.2

  • Option 2)

    552.7

  • Option 3)

    390.7

  • Option 4)

    217.5

 

Answers (1)
V Vakul

As we learnt in

Formula for limiting molar conductivity for electrolyte -

\Lambda_{m}^{0}= \lambda _{+}^{0}.\nu _{+}\:+\:\nu _{-}.\lambda_{-}^{0}

\lambda _{+}^{0}\:and\:\lambda_{-}^{0}

are limiting molar conductivities of cation and anion respectively.

- wherein

if an electrolyte on dissociation gives \nu_{+} \:cation\:and\: \nu_{-} anions.

 

  

\Lambda ^{\infty }_{AcOH}=\Lambda ^{\infty }_{AcONa}+\Lambda ^{\infty }_{HCl}-\Lambda ^{\infty }_{NaCl}

=91.0+426.2-126.5

=390.7\, S\, cm^{2}\, mol^{-1}


Option 1)

517.2

This option is incorrect.

Option 2)

552.7

This option is incorrect.

Option 3)

390.7

This option is correct.

Option 4)

217.5

This option is incorrect.

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