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  • Stuck here, help me understand: - Redox Reaction and Electrochemistry - JEE Main

Calculate molar conductance of acetic acid using appropriate molar conductances of the electrolytes listed above at infinite dilution in H_{2}O at 25°C.

  • Option 1)

    517.2

  • Option 2)

    552.7

  • Option 3)

    390.7

  • Option 4)

    217.5

 

Answers (1)

As we learnt in

Formula for limiting molar conductivity for electrolyte -

\Lambda_{m}^{0}= \lambda _{+}^{0}.\nu _{+}\:+\:\nu _{-}.\lambda_{-}^{0}

\lambda _{+}^{0}\:and\:\lambda_{-}^{0}

are limiting molar conductivities of cation and anion respectively.

- wherein

if an electrolyte on dissociation gives \nu_{+} \:cation\:and\: \nu_{-} anions.

 

  

\Lambda ^{\infty }_{AcOH}=\Lambda ^{\infty }_{AcONa}+\Lambda ^{\infty }_{HCl}-\Lambda ^{\infty }_{NaCl}

=91.0+426.2-126.5

=390.7\, S\, cm^{2}\, mol^{-1}


Option 1)

517.2

This option is incorrect.

Option 2)

552.7

This option is incorrect.

Option 3)

390.7

This option is correct.

Option 4)

217.5

This option is incorrect.

Posted by

Vakul

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