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N_{2} + 3H_{2}\rightarrow2NH_{3}

After completion of 75% of the reaction what would be the mole fraction for the constituents ?

  • Option 1)

    0.1, 0.3, 0.6

  • Option 2)

    0.3, 0.1, 0.6

  • Option 3)

    0.6, 0.1, 0.3

  • Option 4)

    0.1, 0.6, 0.3

 

Answers (1)

As we learnt 

 

Mole Fraction -

It is ratio of moles of solute or moles of solvent to moles of solution.

- wherein

If a substance ‘A’ dissolves in substance ‘B’ and their number of moles are n_{A} and n_{B} respectively; then the mole fractions of A and B are given as

Mole fraction of A = (number of moles of A)/(number of moles of solution ) = n_{A}/(n_{A}+ n_{B})

 

 

 At   t = \frac{3}{4},

                N_{2} + 3H_{2}\rightarrow2NH_{3}

t = \frac{3}{4}     \frac{1}{4}            \frac{3}{4}                \frac{3}{2}

Moles of N2 = 0.25

Moles of H2 = 0.75

Moles of NH3 = 1.5

Mole fraction of N2

\frac{0.25}{2.5} =0.1

Mole fraction of H2 

\frac{0.75}{2.5} =0.3

Mole fraction of NH3 

\frac{1.5}{2.5} =0.6

 


Option 1)

0.1, 0.3, 0.6

Option 2)

0.3, 0.1, 0.6

Option 3)

0.6, 0.1, 0.3

Option 4)

0.1, 0.6, 0.3

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