The maximum possible denticities of a ligand given below towards a common transition and inner - transition metal ion , respectively, are :
8 and 6
6 and 8
6 and 6
8 and 8
Generally the denticity of the ligand is double of the oxidation state of the metal ion...
HENCE the given ligand will act as hexadentate towards transition elements because the common oxidation state shown by them is +3 whereas in case of inner transition metal ion, it's denticity is 8 because their common oxidation state is +4.
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Coordination number -
No. of ligands which are bounded directly to metal
- wherein
eg:![\left [ Ni\left ( NH_{3} \right )_{4} \right ]^{2+}](https://learn.careers360.com/latex-image/?%5Cleft%20%5B%20Ni%5Cleft%20%28%20NH_%7B3%7D%20%5Cright%20%29_%7B4%7D%20%5Cright%20%5D%5E%7B2+%7D)
Coordination No.
eg:![\left [Co\left ( en\right )_{3} \right ]^{3+}](https://learn.careers360.com/latex-image/?%5Cleft%20%5BCo%5Cleft%20%28%20en%5Cright%20%29_%7B3%7D%20%5Cright%20%5D%5E%7B3+%7D)
Coordination No.
en is bidentate
Co-ordination number towards a common transition element (3d) = 6
CN of inner transition element = 8 to 12
so option 6,8 will be correct.
Option 1)
8 and 6
Option 2)
6 and 8
Option 3)
6 and 6
Option 4)
8 and 8