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  • Stuck here, help me understand: The maximum possible denticities of a ligand given below towards a common transition and inner - transition metal ion , respectively, are :

The maximum possible denticities of a ligand given below towards a common transition and inner - transition metal ion , respectively, are  :

  • Option 1)

    8 and 6

  • Option 2)

    6 and 8

  • Option 3)

    6 and 6

  • Option 4)

    8 and 8

Answers (2)

best_answer

 

Coordination number -

No. of ligands which are bounded directly to metal

 

- wherein

eg: \left [ Ni\left ( NH_{3} \right )_{4} \right ]^{2+}

Coordination No. \left ( CN \right )= 4

eg: \left [Co\left ( en\right )_{3} \right ]^{3+} 

Coordination No. \left ( CN \right )= 6

en is bidentate

en\rightarrow H_{2}N-CH_{2}-CH_{2}-NH_{2}

 

 

 

 

Co-ordination number towards a common transition element (3d) =  6

CN of inner transition element = 8 to 12

so option 6,8 will be correct.


Option 1)

8 and 6

Option 2)

6 and 8

Option 3)

6 and 6

Option 4)

8 and 8

Posted by

solutionqc

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Generally the denticity of the ligand is double of the oxidation state of the metal ion...

HENCE the given ligand will act as hexadentate towards transition elements because the common oxidation state shown by them is +3 whereas in case of inner transition metal ion, it's denticity is 8 because their common oxidation state is +4. 

Posted by

DIVYANSHI GUPTA

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