Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Stuck here, help me understand: The ratio of a number of atoms present in a simple cubic, body-centered cubic and face-centered cubic structure are, respectively:

The ratio of a number of atoms present in a simple cubic, body-centered cubic and face-centered cubic structure are, respectively:

 

  • Option 1)

    8 : 1 : 6

  • Option 2)

    1 : 2 : 4

  • Option 3)

    4 : 2 : 1

  • Option 4)

    4 : 2 : 3

 

Answers (1)

best_answer

 

No. of atoms(z) for simple cubic unit cell -

Lattice points: at corners

For simple cubic (SC), z=1

- wherein

 

 

 

No. of atoms(z) for face centered unit cell -

Lattice points: at corners and face centers of unit cell.

For face centered cubic (FCC), z=4.

- wherein

 

 

 

z for body centered unit cell -

Lattice points: at corners and body center of unit cell.

For body centered cubic (BCC), z=2

- wherein

 

 

 

In SC- lactic point present only at corner =\frac{1}{8}\times 8=1

In BCC batting point present at corner + Body centered = \frac{1}{8}\times 8+1=2

In FCC lattice point present at corner + face centre = \frac{1}{8}\times 8+\frac{1}{2}\times 6=4

1 : 2 : 4


Option 1)

8 : 1 : 6

Option 2)

1 : 2 : 4

Option 3)

4 : 2 : 1

Option 4)

4 : 2 : 3

Posted by

Plabita

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2024 Topper: Farmer’s son Gajare Nilkrishna says ‘keep questioning until you understand’
anam-khan

NIT Puducherry Cut-off 2024: Computer Science and Engineering had highest closing rank last year
anam-khan

What after JEE Main results 2024? All you need to know about JEE Adv, CSAB, JoSAA counselling

Latest Question