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The ratio of root mean square velocity to average velocity of gas molecules at a particular temperature is

  • Option 1)

    1.086 : 1

  • Option 2)

     1 : 1.086

  • Option 3)

     2 : 1.086

  • Option 4)

    1.086 : 2

 

Answers (1)

best_answer

As we learnt in 

Average speed of gas molecules -

Vavg=\sqrt{(8RT/\pi M)}

- wherein

M- Molecular Mass , R- Gas Constant , T- Temperature

 

V_{rms}= \sqrt{\frac{3RT}{M}},V_{av}= \sqrt{\frac{8RT}{\pi M}};\frac{V_{rms}}{V_{av}}= \sqrt{\frac{3\pi }{8}}

= \sqrt{\frac{66}{56}}\Rightarrow \frac{1.086}{1}


Option 1)

1.086 : 1

Correct

Option 2)

 1 : 1.086

Incorrect

Option 3)

 2 : 1.086

Incorrect

Option 4)

1.086 : 2

Incorrect

Posted by

divya.saini

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