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The ratio of work done by an ideal monoatomic gas to the heat supplied to it in an isobaric process is :


  • Option 1)


  • Option 2)


  • Option 3)


  • Option 4)



Answers (1)


As we learnt in

Specific heat capacity at constant pressure -

C_{p}= C_{v}+R

= \left ( \frac{f}{2}+1 \right )R

- wherein

f = degree of freedom

R= Universal gas constant


 Work done in isobaric process =nR\Delta T

Heat supplied =nC_{p} \Delta T

    =nR\left(\frac{f}{2}+1 \right )\Delta T=\frac{5}{2}(nR\Delta T)

Ratio =\frac{nR\Delta T}{\frac{5}{2}(nR\Delta T)}=\frac{2}{5}

Correct option is 4.

Option 1)


This is an incorrect option.

Option 2)


This is an incorrect option.

Option 3)


This is an incorrect option.

Option 4)


This is the correct option.

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