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X ml of H2 gas effuses through a hole in a container in 5 sec. The time taken for the effusion of the same volume of the  gas specified below under identical conditions is :

  • Option 1)

    10 sec He

  • Option 2)

    20 sec O2

  • Option 3)

    25 sec CO2

  • Option 4)

    55 sec CO2

 

Answers (1)

As we learnt in

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

\frac{r_{1}}{r_{2}}= \frac{t_{2}}{5}= \sqrt{\frac{M_{2}}{2}}, t_{2} = 20 \: \: sec \: and \: M_{2} = 32

 


Option 1)

10 sec He

Incorrect

Option 2)

20 sec O2

Correct

Option 3)

25 sec CO2

Incorrect

Option 4)

55 sec CO2

Incorrect

Posted by

Vakul

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