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Suppose that the intensity of laser as \left ( \frac{315}{\pi } \right )\frac{\omega }{m^{2}}. The rms electric field, in units of  \frac{v}{m}  associated with this sources is close to the nearest integer is :-______. Take \epsilon _{0}=8.86\times 10^{-12}C^{2}Nm^{-2}, C=3\times 10^{2}m/s  
Option: 1 194
Option: 2 275
Option: 3 378
Option: 4 467

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\begin{array}{l} \because 1=\frac{1}{2} \varepsilon_{0} E_{0}^{2} c \\ \Rightarrow E_{0}=\sqrt{\frac{21}{\varepsilon_{0} c}} \\ \therefore E_{r m s}=\frac{E_{0}}{\sqrt{2}}=\sqrt{\frac{1}{\varepsilon_{0} c}} \\ =\sqrt{\frac{315}{\pi} \times \frac{1}{8.86 \times 10^{-12} \times 3 \times 10^{8}}} \\ =194 \end{array}

 

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Deependra Verma

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