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  • Suppose, the daughter nucleus in a nuclear decay is itself radioactive. Let and <img alt="\mathrm{\lambda_d}" src="/l

Suppose, the daughter nucleus in a nuclear decay is itself radioactive. Let \mathrm{\lambda_p} and \mathrm{\lambda_d} be the decay constant of the parent and the daughter nuclei. Also, let \mathrm{N_p} and \mathrm{N_d} be the number of parent and daughter nuclei at time \mathrm{t}. Find the condition for which the number of daughter nuclei become constant.

Option: 1

\mathrm{\lambda_ p A_ p=\lambda_dA_d}


Option: 2

\mathrm{A_p=-A_d}


Option: 3

\mathrm{\lambda_pN_p=\lambda_d N_d}


Option: 4

\mathrm{A_p=2A_d}


Answers (1)

best_answer

\mathrm{ A_p=A_d}
but \mathrm{A=N \cdot \lambda } then
\mathrm{\lambda_pN_p=\lambda_d \ N_d}

Posted by

vishal kumar

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