Take the breakdown voltage of the zener diode used in the given circuit as 6V. For the input voltage shown in the figure below, the time variation of the output voltage is : (graphs drawn schematic and not to scale)
Option: 1
Option: 2
Option: 3
Option: 4
As there are two Zener diodes in reverse polarity, so if one is in forward bias the other will be in reverse bias and above 6 V the reverse bias will too be in conduction mode. Therefore when the voltage is more than 6 V the output will be constant. And when it is less than 6 V it will follow the input voltage.
so the correct graph is given as
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