Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Tangents are drawn to the circle at the points where it is meet by t

Tangents are drawn to the circle \mathrm{x^2+y^2=12} at the points where it is meet by the circle \mathrm{x^2+y^2-5 x+3 y-2=0}, then the x-coordinate of the point of intersection of these tangents is __________.

Option: 1

6


Option: 2

10


Option: 3

8


Option: 4

7


Answers (1)

best_answer

The circles are given as \mathrm{x^2+y^2=12} and \mathrm{x^2+y^2-5 x+ 3 y-2=0}

Common chord AB is \mathrm{5 x-3 y-10=0}. Let the coordinates of P be \mathrm{(\alpha, \beta)}

Equation of the chord of contact of F(\alpha, \beta) with respect to

x^2+y^2=12 is x \alpha+y \beta-12=0

Comparing the coefficients of common chord AB and

chord of contact is \frac{\alpha}{5}=\frac{\beta}{-3}=\frac{-12}{-10} \Rightarrow \alpha=6, \beta=-\frac{18}{5}

\therefore x-coordinate is 6 .

 

Posted by

Irshad Anwar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 1 exam in the last week of January; registration details
anam-khan

Over 656 UPSC, JEE, NEET, other coaching aspirants refunded more than Rs 1 crore: Govt
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET, UGC NET dates soon; websites to check

Latest Question