# Consider the hydrated ions of $Ti^{2+},V^{2+},Ti^{3+}\: \: and\: \: Sc^{3+}$.The correct order of their spin-only magnetic moments is:Option 1)$V^{2+}Option 2)$Sc^{3+}Option 3)$Ti^{3+}Option 4)$Sc^{3+}

Spin-only magnetic moment is more for the elements whose number of unpaired electrons are higher.

$\therefore$ Spin-only magnetic moment $\propto$ n (number of unpaired electrons)

Now,

$Sc^{3+}$ = $3d^{0}$ ( n = 0)

$Ti^{3+}$ = $3d^{1}$ ( n = 1)

$Ti^{2+}$ = $3d^{2}$ ( n = 2)

$V^{2+}$ = $3d^{3}$ ( n = 3 )

$\therefore$ Correct order is : $Sc^{3+}

So, option (2) is correct.

Option 1)

$V^{2+}

Option 2)

$Sc^{3+}

Option 3)

$Ti^{3+}

Option 4)

$Sc^{3+}

### Preparation Products

##### Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
##### Rank Booster JEE Main 2020

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 9999/- ₹ 4999/-
##### Test Series JEE Main Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 1999/-
##### Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-