Consider the hydrated ions of $Ti^{2+},V^{2+},Ti^{3+}\: \: and\: \: Sc^{3+}$.The correct order of their spin-only magnetic moments is:Option 1)$V^{2+}Option 2)$Sc^{3+}Option 3)$Ti^{3+}Option 4)$Sc^{3+}

S solutionqc

Spin-only magnetic moment is more for the elements whose number of unpaired electrons are higher.

$\therefore$ Spin-only magnetic moment $\propto$ n (number of unpaired electrons)

Now,

$Sc^{3+}$ = $3d^{0}$ ( n = 0)

$Ti^{3+}$ = $3d^{1}$ ( n = 1)

$Ti^{2+}$ = $3d^{2}$ ( n = 2)

$V^{2+}$ = $3d^{3}$ ( n = 3 )

$\therefore$ Correct order is : $Sc^{3+}

So, option (2) is correct.

Option 1)

$V^{2+}

Option 2)

$Sc^{3+}

Option 3)

$Ti^{3+}

Option 4)

$Sc^{3+}

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