Consider the hydrated ions of Ti^{2+},V^{2+},Ti^{3+}\: \: and\: \: Sc^{3+}.

The correct order of their spin-only magnetic moments is:

  • Option 1)

    V^{2+}<Ti^{2+}<Ti^{3+}<Sc^{3+}

  • Option 2)

    Sc^{3+}<Ti^{3+}<Ti^{2+}<V^{2+}

  • Option 3)

    Ti^{3+}<Ti^{2+}<Sc^{3+}<V^{2+}

  • Option 4)

    Sc^{3+}<Ti^{3+}<V^{2+}<Ti^{2+}

Answers (1)
S solutionqc

Spin-only magnetic moment is more for the elements whose number of unpaired electrons are higher.

\therefore Spin-only magnetic moment \propto n (number of unpaired electrons)

Now,

Sc^{3+} = 3d^{0} ( n = 0)

Ti^{3+} = 3d^{1} ( n = 1)

Ti^{2+} = 3d^{2} ( n = 2) 

V^{2+} = 3d^{3} ( n = 3 )

\therefore Correct order is : Sc^{3+}<Ti^{3+}<Ti^{2+}<V^{2+}

So, option (2) is correct.


Option 1)

V^{2+}<Ti^{2+}<Ti^{3+}<Sc^{3+}

Option 2)

Sc^{3+}<Ti^{3+}<Ti^{2+}<V^{2+}

Option 3)

Ti^{3+}<Ti^{2+}<Sc^{3+}<V^{2+}

Option 4)

Sc^{3+}<Ti^{3+}<V^{2+}<Ti^{2+}

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