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$\lim_{x \to b}\frac{\sqrt{x-a}-\sqrt{b-a}}{x^{2}-b^{2}}$

Option 1)
$\frac{1}{4b\sqrt{a-b}}$

Option 2)
$\frac{1}{4b\sqrt{b-a}}$

Option 3)
$\frac{1}{4a\sqrt{a-b}}$

Option 4)
$\frac{1}{b\sqrt{b-a}}$

Answers (1)

best_answer

As we learnt in

Method of Rationalisation -

Rationalisation method is used when we have RADICAL SIGNS in an expression.(like 1/2, 1/3 etc) and there exists a negative sign between two terms of an algebraic expression.

- wherein

$\lim_{x\rightarrow a}\:\frac{x-a}{\sqrt{x}-\sqrt{a}}$

$\therefore \:\frac{(x-a)(\sqrt{x}+\sqrt{a})}{(\sqrt{x}-\sqrt{a})(\sqrt{x}+\sqrt{a})}$

$=\sqrt{x}+\sqrt{a}$

$=\sqrt{a}+\sqrt{a}$

$=2\sqrt{a}$

$\lim_{x\rightarrow b}\frac{\sqrt{x-a}-\sqrt{b-a}}{x^{2}-b^{2}}$

$\Rightarrow \lim_{x\rightarrow b}\frac{\sqrt{x-a}-\sqrt{b-a}}{x^{2}-b^{2}} \times \frac{\sqrt{x-a}+\sqrt{b-a}}{\sqrt{x-a}+\sqrt{b-a}}$

$= \lim_{x\rightarrow b} \frac{(x-a)-(b-a)}{(x^{2}-b^{2})\left(\sqrt{x-a}+\sqrt{b-a} \right )}$

$= \lim_{x\rightarrow b} \frac{(x-b)}{(x^{2}-b^{2})\left(\sqrt{x-a}+\sqrt{b-a} \right )}$

$= \lim_{x\rightarrow b} \frac{1}{(x+b)\left(\sqrt{x-a}+\sqrt{b-a} \right )}$

$= \lim_{x\rightarrow b} \frac{1}{2b \times 2 \sqrt{b-a}}=\frac{1}{4b \sqrt{b-a}}$

Option 1)

$\frac{1}{4b\sqrt{a-b}}$

Incorrect

Option 2)

$\frac{1}{4b\sqrt{b-a}}$

Correct

Option 3)

$\frac{1}{4a\sqrt{a-b}}$

Incorrect

Option 4)

$\frac{1}{b\sqrt{b-a}}$

Incorrect

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