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Given the reaction between 2 gases represented by A2 and B2 to give the compound AB(g).

A2(g) + B2(g) \rightleftharpoons 2 AB(g).

At equilibrium, the concentration

of A2 = 3.0 x 10-3 M

of B2 = 4.2 x 10-3 M

of AB = 2.8 x 10-3 M

If the reaction takes place in a sealed vessel at 527oC, then the value of Kc will be:

  • Option 1)

    1.9

  • Option 2)

    0.62

  • Option 3)

    4.5

  • Option 4)

    2.0

 

Answers (1)

As learnt in 

A_{2}(g)+B_{2}(g)\rightleftharpoons 2AB(g)

K_{C}= \frac{[AB]^{2}}{[A_{2}]\:[B_{2}]}

[AB]=2.8 \times 10^{-3}M

[A_{2}]=3 \times 10^{-3}M

[B_{2}]=4.2 \times 10^{-3}M

K_{C}=\frac{(2.8 \times 10^{-3})^{2}}{(3 \times 10^{-3})\:(4.2 \times 10^{-3})}

\frac{7.84}{12.6}=0.62


Option 1)

1.9

This option is incorrect.

Option 2)

0.62

This option is correct.

Option 3)

4.5

This option is incorrect.

Option 4)

2.0

This option is incorrect.

Posted by

Vakul

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