Hinsberg's reagent is : Option 1) $C_{6}H_{5}COCl$ Option 2) $SOCl_{2}$ Option 3) $C_{6}H_{5}SO_{2}Cl$ Option 4) $\left ( COCl \right )_{2}$

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The Hinsberg Test -

This test can be used to demonstrate whether an amine is primary, secondary or tertiary.Primary amines react with benzene sulfonyl chloride to form N - substituted benzene sulfonamides.These, in turn, undergo acid-base reactions with the excess potassium hydroxide to form water soluble potasssium salt. Acidification of this solution will cause the water soluble in the next stage, cause the water- insoluble  N - substituted sulfonamide to precipitate.

- wherein

$C_{6}H_{5}SO_{2}Cl$ is Hinsberg's reagent,

Hinsberg's reagent is used for the detection of primary, secondary and tertiary amine

$C_{6}H_{5}SO_{2}Cl+\:-NH_{2}(P.A.)\rightarrow soluble\:\:in\:\:alkali$

$C_{6}H_{5}SO_{2}Cl+\:-NH-(S.A.)\rightarrow insoluble\:\:in\:\:alkali$

$C_{6}H_{5}SO_{2}Cl+$     $(T.A.)\rightarrow No\:\:reaction$

Option 1)

$C_{6}H_{5}COCl$

Option 2)

$SOCl_{2}$

Option 3)

$C_{6}H_{5}SO_{2}Cl$

Option 4)

$\left ( COCl \right )_{2}$

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